Integrand size = 29, antiderivative size = 52 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=\frac {2 i \cos ^3(c+d x)}{3 a^2 d}+\frac {\sin (c+d x)}{a^2 d}-\frac {2 \sin ^3(c+d x)}{3 a^2 d} \]
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Time = 0.13 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.207, Rules used = {3171, 3169, 2713, 2645, 30, 2644} \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=-\frac {2 \sin ^3(c+d x)}{3 a^2 d}+\frac {\sin (c+d x)}{a^2 d}+\frac {2 i \cos ^3(c+d x)}{3 a^2 d} \]
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Rule 30
Rule 2644
Rule 2645
Rule 2713
Rule 3169
Rule 3171
Rubi steps \begin{align*} \text {integral}& = -\frac {\int \cos (c+d x) (i a \cos (c+d x)+a \sin (c+d x))^2 \, dx}{a^4} \\ & = -\frac {\int \left (-a^2 \cos ^3(c+d x)+2 i a^2 \cos ^2(c+d x) \sin (c+d x)+a^2 \cos (c+d x) \sin ^2(c+d x)\right ) \, dx}{a^4} \\ & = -\frac {(2 i) \int \cos ^2(c+d x) \sin (c+d x) \, dx}{a^2}+\frac {\int \cos ^3(c+d x) \, dx}{a^2}-\frac {\int \cos (c+d x) \sin ^2(c+d x) \, dx}{a^2} \\ & = \frac {(2 i) \text {Subst}\left (\int x^2 \, dx,x,\cos (c+d x)\right )}{a^2 d}-\frac {\text {Subst}\left (\int x^2 \, dx,x,\sin (c+d x)\right )}{a^2 d}-\frac {\text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{a^2 d} \\ & = \frac {2 i \cos ^3(c+d x)}{3 a^2 d}+\frac {\sin (c+d x)}{a^2 d}-\frac {2 \sin ^3(c+d x)}{3 a^2 d} \\ \end{align*}
Time = 0.45 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.40 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=\frac {i \cos (c+d x)}{2 a^2 d}+\frac {i \cos (3 (c+d x))}{6 a^2 d}+\frac {\sin (c+d x)}{2 a^2 d}+\frac {\sin (3 (c+d x))}{6 a^2 d} \]
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Time = 0.53 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.73
method | result | size |
risch | \(\frac {i {\mathrm e}^{-i \left (d x +c \right )}}{2 a^{2} d}+\frac {i {\mathrm e}^{-3 i \left (d x +c \right )}}{6 a^{2} d}\) | \(38\) |
derivativedivides | \(\frac {\frac {2 i}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i\right )^{2}}-\frac {4}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i\right )^{3}}+\frac {2}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i}}{a^{2} d}\) | \(57\) |
default | \(\frac {\frac {2 i}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i\right )^{2}}-\frac {4}{3 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i\right )^{3}}+\frac {2}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i}}{a^{2} d}\) | \(57\) |
norman | \(\frac {\frac {4 i \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{a d}+\frac {4 i}{3 a d}+\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a d}-\frac {4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 a d}+\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{a d}}{a \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{3}}\) | \(105\) |
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Time = 0.24 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.58 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=\frac {{\left (3 i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i\right )} e^{\left (-3 i \, d x - 3 i \, c\right )}}{6 \, a^{2} d} \]
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Time = 0.13 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.77 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=\begin {cases} \frac {\left (6 i a^{2} d e^{3 i c} e^{- i d x} + 2 i a^{2} d e^{i c} e^{- 3 i d x}\right ) e^{- 4 i c}}{12 a^{4} d^{2}} & \text {for}\: a^{4} d^{2} e^{4 i c} \neq 0 \\\frac {x \left (e^{2 i c} + 1\right ) e^{- 3 i c}}{2 a^{2}} & \text {otherwise} \end {cases} \]
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Time = 0.23 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.87 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=\frac {i \, \cos \left (3 \, d x + 3 \, c\right ) + 3 i \, \cos \left (d x + c\right ) + \sin \left (3 \, d x + 3 \, c\right ) + 3 \, \sin \left (d x + c\right )}{6 \, a^{2} d} \]
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Time = 0.30 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.90 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=\frac {2 \, {\left (3 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 3 i \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 2\right )}}{3 \, a^{2} d {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - i\right )}^{3}} \]
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Time = 22.73 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.52 \[ \int \frac {\cos (c+d x)}{(a \cos (c+d x)+i a \sin (c+d x))^2} \, dx=-\frac {2\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,3{}\mathrm {i}+3\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )-2{}\mathrm {i}\right )}{3\,a^2\,d\,\left (-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,1{}\mathrm {i}-3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,3{}\mathrm {i}+1\right )} \]
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